Transcript Example 21 If pth, qth, rth and sth terms of an AP are in GP, then show that (p – q), (q – r), (r – s) are also in GP We know that the nth term of AP is a (n – 1)d ie an = a (n – 1)d It is given that ap, aq, ar & as in GP ie their common ratio is same So,𝑎_𝑞/𝑎_𝑝 = (ar )/qq = 𝑎𝑠/𝑎𝑟 We need to show (p – q), (q – r), (r – s) are in If 2P = 3Q = 4R, Then P Q R = ?No matter you take k or 1 By taking 2P = 3Q = 4R = 1, we have P = ½ Q= 1/3 and R = ¼ So ratio = ½ 1/3 ¼ = 6 4 3 (taking LCM as 12)
In The Figure Pqrs Is A Parallelogram If P 75 O Then Q
